https://www.researchgate.net/
https://searchnetworking.techtarget.com/definition/dense-wavelength-division-multiplexing-DWDM
D3 Teknik Informatika USU 2018
Fakultas Matematika dan Ilmu Pengetahuan Alam Universitas Sumatera Utara
Rabu, 11 September 2019
Materi
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Date
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Topic
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Reading and Homework
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Week 1
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Computer Network Syllabus
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Week 2
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Computer Network Timeline
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Week 3
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Type Of Computer Network
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Week 4
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Component of Computer Network
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Week 5
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UTP dan STP in a Computer Network
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Week 6
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Coaxial Cable in a Computer Network
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Week 7
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Broadband and Baseband
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Week 8
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Fiber Optic
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Week 9
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Infrared and Radio Waves
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Week 10
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Satellite Base in Computer Network
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Week 11
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Network Topology
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Week 12
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Physical topology
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Week 13
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Logical Topology
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Week 14
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IP Address
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Week 15
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Subnetting
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Week 16
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Computer Network Configuration
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Rabu, 15 Mei 2019
TUGAS ARKOM 3 KELOMPOK 1
Kelompok
1 :
1. Desi
Sandra Geovany Boangmanalu (182406054)
2. Devia
Maharani Tarigan (182406056)
3. Wilter
Leonardo Hutapea (182406066)
4. Hafiz
Maulana Rangkuti (182406077)
5. Rifqihaji
Atharid Siagian (182406078)
Tugas Arsitektur
Komputer 3
1. Tulislah
nilai desimal dari bilangan biner 10101010
Jawaban:
10101010 = (1x27) + (0x26) +
(1x25) + (0x24) + (1x23) + (0x22) +
(1x21) + (0x20) = 128 + 32 + 8 + 2 = 170
Jadi, 10101010(2) = 170(10)
2. Tulislah
nilai desimal dari bilangan oktal 123456
Jawaban:
Pertama bilangan oktal dibuah ke biner menjadi
123456(8) = 001010011100101110(2)
Kemudian dari biner diubah ke desimal
001010011100101110 = (1x21) + (1x22)
+ (1x23) + (1x25) + (1x28) + (1x29)
+ (1x210) + (1x214) + (1x216) = 2 + 4 + 8 + 32
+ 256 + 512 + 1024 + 8192 + 32768 = 42798
Jadi 123456(8) = 001010011100101110(2)
= 42798(10)
3. Tuliskan
nilai desimal dari bilangan heksadesimal 37f
Jawaban:
Pertama bilangan heksadesimal diubah ke biner
menjadi 37F(16) = 001101111111(2)
Kemudian dari biner diubah ke heksadesimal
001101111111 = (1x20) + (1x21) + (1x22) +
(1x23) + (1x24) + (1x25) + (1x26) +
(1x28) + (1x29) = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 256 +
512 = 895
Jadi 37F(16) = 001101111111(2)
= 895(10)
4. Tentukanlah
nilai biner dari bilangan desimal 8192
Jawaban:
8192 = 8192 – (1 x 214) = 0
Maka 8129 = (0x20) + (0x21) + (0x22) +
(0x23) + (0x24) + (0x25) + (0x26) +
(0x27) + (0x28) + (0x29) + (0x210) + (0x211) +
(0x212) + (0x213) + (1x214)
Jadi 8192(10) = 10000000000000(2)
5. Tentukanlah
nilai bilangan oktal dari bilangan desimal 1024
Jawaban:
Pertama bilangan desimal diubah ke biner menjadi
1024(10) = 001000010100(2)
Kemudian dari biner diubah menjadi oktal
001000010100 = (1x22) + (1x24) + (1x29) = 4 +
16 + 512 = 532
Jadi 1024(10) = 001000010100(2) =
532(8)
6. Tentukanlah
hexadesimal dari bilangan desimal 65535
Jawaban:
65535
16--------15
4095
16---------15
255
16---------15
15
16--------15
4095
16---------15
255
16---------15
15
Jadi 65535(10) = FFFF(16)
7. Ubahlah
bilangan desimal 65535 kedalam bilangan biner
Jawaban:
65535
2---------1
32767
2----------1
16383
2-----------1
8191
2-----------1
4095
2-----------1
2047
2-----------1
1023
2-----------1
511
2-----------1
255
2-----------1
127
2-----------1
63
2-----------1
31
2-----------1
15
2-----------1
7
2-----------1
3
2-----------1
1
2---------1
32767
2----------1
16383
2-----------1
8191
2-----------1
4095
2-----------1
2047
2-----------1
1023
2-----------1
511
2-----------1
255
2-----------1
127
2-----------1
63
2-----------1
31
2-----------1
15
2-----------1
7
2-----------1
3
2-----------1
1
Jadi 65535(10) = 1111111111111111(2)
8. Ubahlah
bilangan biner 1111111111111111 menjadi heksadesimal
Jawaban:
1111
| 1111 | 1111 | 1111
15 15 15 15
F F F F
15 15 15 15
F F F F
Jadi 1111111111111111(2) = FFFF(16)
9. Ubahlah
bilangan biner 1111111111111111 menjadi bilangan desimal dan heksadesimal
Jawaban:
1111111111111111 = (1x20) + (1x21) + (1x22) + (1x23)
+ (1x24) + (1x25) + (1x26) + (1x27)
+ (1x28) + (1x29)
+ (1x210) + (1x211) + (1x212) + (1x213)
+ (1x214) + (1x215)
= 65535
1111
| 1111 | 1111 | 1111
15 15 15 15
F F F F
15 15 15 15
F F F F
1111111111111111(2) = 65535(10)
= FFFF(16)
Langganan:
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